6/1/2023 0 Comments Vulgar fraction converterAs it's an improper fraction, convert it to a mixed number: 32 ¹³ / ₁₆ " 32 ¹³/₁₆" 32¹³/₁₆" (you can use the modulo operation to find the quotient quickly). Divide both numerator and denominator by 2, so we get ⁵²⁵ / ₁₆ " ⁵²⁵/₁₆" ⁵²⁵/₁₆". ![]() Find the least common multiple of 1050 and 32, which is 2. Here is how to deal with the problem:ĭivide 5 m by 6, 5 m / 6 = 5 / 6 m 5 \text 1050 in.įinally, we can convert the length from inches to fraction: ¹⁰⁵⁰ / ₃₂ " ¹⁰⁵⁰/₃₂" ¹⁰⁵⁰/₃₂".Īs there are countless equivalent fractions to our result (try Omni's equivalent fractions calculator for the proof), we can make our lives easier by simplifying this inch fraction. We can measure the length with precision down to ¹/₃₂". ![]() You plan to cut it into six equal parts, but you have only a tape measure with the fractional inches scale. Unfortunately we cannot merge the code paths for conversion to Fraction of both cases since the denominator limitation will return incorrect results for large denominators in case 1.Imagine you've bought a wooden panel, 5 meters long. Unfortunately the intermediate representation as a floating point value loses some precision and we need to approximate the intended value using Fraction.limit_denominator and the knowledge of the largest occurring denominator 1,000,000 (actually 10 but the function’s default argument value is good enough). Case 2: input length = 1 Fraction(unicodedata.numeric(s)).limit_denominator(10)Ĭonvert the input codepoint into its floating point representation using unicodedata.numeric and subsequently as a Fraction. Python 3, 153 151 bytes lambda s:F(s.translate() ) See this 05AB1E tip of mine (section How to compress large integers?) to understand how all the compressed integers work. # (after which the result is output implicitly) ÕE # Loop "" amount of times, resulting in an error ` # Push both values separated to the stackĭ_i # If the top value (the denominator) is 0: Ë # Else (the first character is not '⅟'): Z # Push 1 divided by the remaining value Åi # If it's in the list (thus the first character was '⅟'): Ć # Extract the first character of the (implicit) input ` # Pop and push both digits separated to the stack È # Use it to index into the list we created earlier Ik # Get the index of the input in this list (As I need the numerator as an integer anyway, incrementing it actually makes the string more compressible.)Ġ5AB1E, 90 88 65 bytes gi up the decremented numerator and denominator in two compressed strings and divide their increments. Handle the ⅟ case by taking the reciprocal of the denominator. Handle the ⁄ case by dividing the numerator by the denominator. look up the ordinal of the input in two compressed strings, one for the numerator, one for the denominator, and then increment the denominator (so that 1/10 can be handled).Īlternative version for 73 bytes: it online! Link is to verbose version of code. Outputs a pair of integers separated with / for convenience. Import as ReadPĬharcoal, 62 bytes it online! Link is to verbose version of code. Ungolfed solution Haskell import Control.Monad It is negative.ġ⁄0 (U 0031 U 2044 U 0030) must make the parser be in erroneous state. ![]() ½ (U 002D U 00BD) falls in don't care situation. ↉ (U 2189) falls in don't care situation. It's an improper fraction.Ĥ⁄8 (U 0034 U 2044 U 0038) falls in don't care situation. It's a whole number.ĩ⁄8 (U 0039 U 2044 U 0038) falls in don't care situation. Note that ⅐ and ⅟7 will parse to the same.Ġ (U 0030) falls in don't care situation. Inputs that are neither valid nor invalid fall in don't care situation. Though native rational number type is preferred, a pair of integers is permitted. Output type and format doesn't matter either. If the denominator is zero, the parser must fall in an erroneous state. ⅟ (U 215F fraction numerator one) followed by ASCII decimal digits (U 0030 – U 0039)ĪSCII decimal digits followed by ⁄(U 2044 fraction slash) followed by ASCII decimal digits Given a string with single Unicode vulgar fraction, parse it to a rational number.
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